

| Subject: | Re: Power loss with 15" wheels |
| From: | Pensioner |
| Date: | Sat, 4 Mar 2006 11:51:52 -0800 |
The discussion is really about torque and thrust. Your engine has a torque curve that relates torque to RPM. This torque is multiplied by the gear train (transmission gear x ring and pinion ratio) and appears as a twisting force or torque at the axle. This torque is applied to the road through a moment arm which is the actual distance from the center of the axle to the ground. For the sake of example call this the rolling radius. For any given engine transmission differential instance the difference in torque with various wheels can be calculated as a percentage. This percentage is the difference between the rolling radii of the two wheels in question. EG: Wheel/tire 'A' has a 13inch rolling radius. Wheel/tire 'B' has a 15inch rolling radius. The reduction in thrust by the larger 'B' wheel over the smaller wheel 'A' is the ratio of the two radii or 13/15. FWIW this process also works for retarding force or braking. A larger wheel will lessen the braking force per unit pressure by a similar ratio. QED or something like that, rigorous proof is left as an excercise for those with too much time on their hands. A useful tool in the form of an MSExcel spreadsheet is available for posting to the Vanagon Yahoo group. Tim Smith is the original author. P
Have something to add on this topic today? Revive this thread in the forum »