

| Subject: | FW: Aux battery & isolator |
| From: | Pollard, Matthew |
| Date: | Tue, 19 Jan 1999 10:36:23 -0800 |
> "Pollard, Matthew" wrote: > > > > thanks for the insight! > > if my memory serves me right, I am supposed to bend a little copper > brush > > that is in the alternator away from it's contact and connect this to a > > specific terminal on the isolator. I'm thinking this bypasses the > internal > > regulator. Sound reasonable? > > -Matthew > > > > Nope, you're still using the internal regulator. BUT... instead of it > taking its measurement from the alternator output, your're shifting it > to measure directly at the battery instead. This automatically > compensates for the voltage drop across the isolator, which otherwise > would leave the batteries undercharged. Note of mild caution: if you > have anything hooked up to the alternator output lead btw the alternator > and isolator, there will be two effects, 1) it will see no power unless > the motor is running, 2) it will see about 3/4 volt more than usual. > > NB - unless they've figured out a tricky circuit, you are taking the > regulator sense voltage from one or the other battery, but not both. So > if one is flat but the sense connection is to the other one, it will > charge slower than you would like. But it *will* charge. I'd suggest > hooking the isolator up so that it senses the house battery, since > that's the one you're going to be running flat. > > Make sense? > > david
Have something to add on this topic today? Revive this thread in the forum »